Tan(x y) = (tan x tan y) / (1 tan x tan y) sin(2x) = 2 sin x cos x cos(2x) = cos ^2 (x) sin ^2 (x) = 2 cos ^2 (x) 1 = 1 2 sin ^2 (x) tan(2x) = 2 tan(x) / (1By dividing the identity sin2 θcos2 θ ≡ 1 by (a) sin2 θ (b) cos2 θ obtain two further identities Hint Recall the definitions of cosecθ, secθ, cotθ Your solution Answer (a) sin 2θ sin2 θ cos2 θ sin 2θ = 1 sin θ (b) sin θ cos 2θ cos2 θ cos θ = 1 cos2 θ 1 cot2θ ≡ cosec2θ tan2 θ 1 ≡ sec2 θ Key Point 13 introduces two further important identities Key PointTan(x y) = (tan x tan y) / (1 tan x tan y) sin(2x) = 2 sin x cos x cos(2x) = cos 2 (x) sin 2 (x) = 2 cos 2 (x) 1 = 1 2 sin 2 (x) tan(2x) = 2 tan(x) / (1
What Is The Formula Of Tan2x Quora
